A Young's double-slit apparatus is set up.A screen is positioned 1.16 m from the double slits,and the spacing between the two slits is 0.0500 mm.The distance between alternating bright fringes is 1.42 cm.What is the light source wavelength? (1 nm = 10−⁹ m) A) 612 nm B) 280 nm C) 490 nm D) 355 nm

Question

Quizplus · Accepted Answer

The wavelength of light can be calculated using the formula for fringe spacing in a double-slit experiment: $ \Delta y = \frac{\lambda L}{d} $. Here, $\Delta y = 1.42 \times 10^{-2} \, \text{m}$, $L = 1.16 \, \text{m}$, and $d = 0.0500 \times 10^{-3} \, \text{m}$. Solving for $\lambda$, we get $\lambda = \frac{\Delta y \cdot d}{L} = \frac{1.42 \times 10^{-2} \cdot 0.0500 \times 10^{-3}}{1.16} \approx 6.12 \times 10^{-7} \, \text{m} = 612 \, \text{nm}$.

A Young's Double-Slit Apparatus Is Set Up