A Young's double-slit apparatus is set up.The source wavelength is 430 nm,and the double-slit spacing is 0.040 mm.At what distance from the double slits should the screen be placed if the spacing between alternating bright fringes is to be 2.6 cm? (1 nm = 10−⁹ m) A) 2.9 m B) 2.4 m C) 2.2 m D) 1.6 m

Question

Quizplus · Accepted Answer

The spacing of the fringes can be calculated using the formula:

Dλ/d = y/D

where:
D = distance from the slits to the screen
λ = wavelength of the light
d = spacing of the double slits
y = distance from the central maximum to the nth fringe

Rearranging the equation, we get:

D = yd/λ

Plugging in the given values, we have:

y = 2.6 cm = 0.026 m
d = 0.040 mm = 4.0 x 10^-5 m
λ = 430 nm = 4.3 x 10^-7 m

D = (0.026 x 4.0 x 10^-5)/4.3 x 10^-7
D = 2.42 m

Therefore, the distance from the double slits to the screen should be approximately 2.4 m for the spacing between alternating bright fringes to be 2.6 cm. Answer B) is the best choice.

A Young's Double-Slit Apparatus Is Set Up