A Young's interference experiment is conducted with blue-green argon laser light (λ = 515 nm).The separation between the slits is 0.50 mm,and the interference pattern appears on a screen 4.95 m away.What is the spacing between the bright fringes? (1 nm = 10−⁹ m) A) 3.4 mm B) 5.1 mm C) 1.7 mm D) 6.8 mm

Question

Quizplus · Accepted Answer

The spacing between the bright fringes can be calculated using the formula:

y = (mλD) / d

where y is the spacing between the bright fringes, m is the order of the fringe (m=0,1,2,...), λ is the wavelength of the light, D is the distance between the slits and the screen, and d is the separation between the slits.

Plugging in the values given in the problem, we get:

y = (0)(515 nm)(4.95 m) / 0.50 mm
y = 5.1 mm

Therefore, the spacing between the bright fringes is 5.1 mm. The correct answer is B.

A Young's Interference Experiment Is Conducted with Blue-Green Argon Laser