A 5.00 g sample of liquid water at 25.0 °C is heated by the addition of 145 J of energy.The final temperature of the water is ________ °C.The specific heat capacity of liquid water is

Question

Quizplus · Accepted Answer

The formula to calculate the change in temperature of a substance is:

ΔT = Q / (m × c)

Where ΔT is the change in temperature, Q is the energy added, m is the mass of the substance, and c is the specific heat capacity.

Plugging in the given values, we get:

ΔT = 145 J / (5.00 g × 4.18 J/g°C) = 6.94°C

Since the initial temperature was 25.0°C, the final temperature would be:

Tf = Ti + ΔT = 25.0°C + 6.94°C = 31.9°C

Therefore, the answer is D) 31.9.

A 500 G Sample of Liquid Water at 25