For 2 NO₂(g)⇌ N₂O₄(g),K_c = [N₂O₄]/[NO₂]².At equilibrium there are 0.0270 mol N₂O₄ and 0.450 mol NO₂ in a 50.0-L container.What is K_c?

Question

Quizplus · Accepted Answer

First, let's write the expression for the equilibrium constant using the coefficients of the balanced equation: K_c = [N₂O₄]/[NO₂]² Then, we can substitute the given equilibrium concentrations: K_c = (0.0270 mol)/(0.450 mol)² K_c = 0.06 Therefore, the answer is choice C (6.67).

For 2 NO2(g)⇌ N2O4(g),Kc = [N2O4]/[NO2]2

For 2 NO₂(g)⇌ N₂O₄(g),K_c = [N₂O₄]/[NO₂]²