A mixture,containing 0.0750 M HCl(g)and 0.0330 M O₂(g)is allowed to come to equilibrium at 480 °C. 4 HCl(g)+ O₂(g)⇌ 2 Cl₂(g)+ 2 H₂O(g) At equilibrium [Cl₂] = 0.030 M.What is the value of K_c?

Question

Quizplus · Accepted Answer

From the balanced equation, we can see that the equilibrium constant expression is: K_c = ([Cl₂]2[H₂O]) / ([HCl]4[O₂]) Substituting the given values at equilibrium: 0.0302 = (0.030)2(2x) / (0.0750)4(0.0330) Simplifying and solving for x: x = [H₂O] = 8.90 × 10^-3 M Substituting all values into the equilibrium constant expression: K_c = (0.0302)(2x) / (0.0750)4(0.0330) = 890 Therefore, the answer is B.

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