What is the empirical formula of a compound that is 66.6% C, 11.2% H, and 22.2% O by mass? A)C₄HO B)C₆HO₂ C)C₈H₁₆O₂ D)C₆H₁₁O E)C₄H₈O

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Quizplus · Accepted Answer

The empirical formula is determined by converting the percentage of each element to moles and finding the simplest whole number ratio. For 66.6% C, 11.2% H, and 22.2% O, the mole ratio simplifies to C: 4, H: 8, O: 1, which corresponds to C₄H₈O.

What Is the Empirical Formula of a Compound That Is