The first-order reaction,SO₂Cl₂ → SO₂ + Cl₂,has a rate constant equal to 2.20 × 10^-5 s^-1 at 593 K.What percentage of the initial amount of SO₂Cl₂ will remain after 2.00 hours?

Question

Quizplus · Accepted Answer

For a first-order reaction, the formula is ln([A]₀/[A]) = kt. Plugging in the values: ln([A]₀/[A]) = (2.20 × 10⁻⁵ s⁻¹)(7200 s). Solving for [A]/[A]₀ gives approximately 0.854, meaning 85.4% remains.

The First-Order Reaction,SO2Cl2 → SO2 + Cl2,has a Rate Constant

The First-Order Reaction,SO₂Cl₂ → SO₂ + Cl₂,has a Rate Constant