At a certain temperature the equilibrium constant,K_c,equals 0.11 for the reaction: 2 ICl(g) ⇌ I₂(g) + Cl₂(g) .
What is the equilibrium concentration of ICl if 0.75 mol of I₂ and 0.75 mol of Cl₂ are initially mixed in a 2.0-L flask?

Question

Quizplus · Accepted Answer

First, we need to use the equilibrium constant equation to set up an expression for the equilibrium concentration of ICl: K_c = [I₂][Cl₂]/[ICl]2 We can plug in the initial concentrations to solve for the equilibrium concentration of ICl: 0.11 = (0.75 mol/L)2 / x2 x2 = (0.75 mol/L)2 / 0.11 x = 0.45 mol/L So the equilibrium concentration of ICl is 0.45 M.

At a Certain Temperature the Equilibrium Constant,Kc,equals 0

At a Certain Temperature the Equilibrium Constant,K_c,equals 0