If 8686 C of charge is passed through molten magnesium chloride, calculate the number of moles of Mg(l)
Produced.

Question

Quizplus · Accepted Answer

The electrolysis of molten magnesium chloride leads to the formation of magnesium metal at the cathode according to the following reaction:

Mg2+(l) + 2e- → Mg(l)

The Faraday constant (F) is defined as the amount of electric charge carried by one mole of electrons and is equal to 96,485 C/mol. Therefore, the number of moles of electrons involved in the reaction is:

n = Q/F = 8686 C / 96,485 C/mol = 0.090 moles of electrons

Since two moles of electrons are required to produce one mole of magnesium, the number of moles of magnesium produced is half of the number of moles of electrons:

n(Mg) = 0.090 /2 = 0.045 mol

Thus, the best choice is B.

If 8686 C of Charge Is Passed Through Molten Magnesium