In the ²³⁸U decay series, there are 8 $\alpha$ particles and 6 $\beta$ particles lost starting with $\alpha$ emission from ²³⁸U.What is the final product?

Question

Quizplus · Accepted Answer

The decay series of ²³⁸U involves the loss of 8 $\alpha$ particles (each reducing the mass number by 4) and 6 $\beta$ particles (each increasing the atomic number by 1), resulting in ²⁰⁶Pb.

In the 238U Decay Series, There Are 8 α\alphaα Particles and 6

In the ²³⁸U Decay Series, There Are 8 $\alpha$ Particles and 6