When ²¹⁴Pb decays as part of the ²³⁸U decay series, there are 2 $\alpha$ particles and 4 $\beta$particles lost starting with $\beta$ emission from ²¹⁴Pb.What is the final product?

Question

Quizplus · Accepted Answer

Starting with ²¹⁴Pb, the decay involves 4 $\beta$ emissions and 2 $\alpha$ emissions. Each $\beta$ emission increases the atomic number by 1, and each $\alpha$ emission decreases the atomic number by 2 and the mass number by 4. After these decays, the final product is ²⁰⁶Pb.

When 214Pb Decays as Part of the 238U Decay Series α\alphaα

When ²¹⁴Pb Decays as Part of the ²³⁸U Decay Series $\alpha$