A gas originally at 27 °C and 1.00 atm pressure in a 3.3 L flask is cooled at constant pressure until the temperature is 11 °C.The new volume of the gas is ________ L.
A)0.27
B)3.1
C)3.3
D)3.5
E)0.24

Question

Quizplus · Accepted Answer

The volume of a gas is directly proportional to its temperature in Kelvin. Using the formula V1/T1 = V2/T2, where T is in Kelvin, convert the temperatures from Celsius to Kelvin (27°C = 300K, 11°C = 284K), and solve for V2. V2 = V1 * (T2/T1) = 3.3 * (284/300) = 3.1 L.

A Gas Originally at 27 °C and 1