The pressure exerted by 1.0 mol of gas in a 13 L flask at 22 °C is ________ kPa.
A)560
B)190
C)18
D)2.4
E)1.0

Question

Quizplus · Accepted Answer

We can use the ideal gas law to solve for the pressure:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to convert the volume from liters to cubic meters (m³):

13 L = 0.013 m³

We also need to convert the temperature from Celsius to Kelvin:

22 °C + 273 = 295 K

Now we can plug in the values and solve for P:

P = nRT/V

P = (1.0 mol)(8.31 J/mol*K)(295 K) / 0.013 m³

P = 190 kPa

Therefore, the answer is B.

The Pressure Exerted by 1