A sample of He gas (2.35 mol)occupies 57.9 L at 300.0 K and 1.00 atm.The volume of this sample is ________ L at 469 K and 1.00 atm.
A)0.709
B)41.1
C)90.5
D)1.41
E)57.9

Question

Quizplus · Accepted Answer

The volume of the gas at the new conditions can be found using Charles's Law, which states that $V_1/T_1 = V_2/T_2$ when the pressure is constant. Given $V_1 = 57.9$ L, $T_1 = 300.0$ K, $T_2 = 469$ K, and $P = 1.00$ atm for both conditions, solving for $V_2$ gives $V_2 = V_1 \times (T_2/T_1) = 57.9 \times (469/300) = 90.5$ L.

A Sample of He Gas (2