What is the rate constant ( )of a first-order process that has a half-life of 550 s?

Question

What is the rate constant (  )of a first-order process that has a half-life of 550 s?

Quizplus · Accepted Answer

The half-life (t1/2) of a first-order reaction is given by the equation:
t1/2 = ln(2)/k
where k is the rate constant.
So, we can rearrange the equation to get:
k = ln(2)/t1/2
Substituting t1/2 = 550 s, we get:
k = ln(2)/550 s ≈ 1.26 × 10^-3 s^-1
Therefore, the rate constant is approximately 1.26 × 10^-3 s^-1, which corresponds to answer choice D).

What Is the Rate Constant ( )Of a First-Order