The decomposition of in solution in carbon tetrachloride proceeds via the reaction 2N₂O₅ (soln) → 4NO₂ (soln) + O₂ (soln)
The reaction is first order and has a rate constant of 4.82 × at 64 °C.If the reaction is initiated with 0.072 mol in a 1.00-L vessel,how many moles remain after 151 s?

Question

The decomposition of The decomposition of in solution in carbon tetrachloride proceeds via the reaction 2N2O5 (soln) → 4NO2 (soln) + O2 (soln) The reaction is first order and has a rate constant of 4.82 × at 64 °C.If the reaction is initiated with 0.072 mol in a 1.00-L vessel,how many moles remain after 151 s? A) 0.067 B) 0.074 C) 0.035 D) 9.6 E) 1.6 ×

The decomposition of in solution in carbon tetrachloride proceeds via the reaction 2N<sub>2</sub>O<sub>5</sub> (soln) → 4NO<sub>2</sub> (soln) + O<sub>2</sub> (soln) The reaction is first order and has a rate constant of 4.82 × at 64 °C.If the reaction is initiated with 0.072 mol in a 1.00-L vessel,how many moles remain after 151 s? A) 0.067 B) 0.074 C) 0.035 D) 9.6 E) 1.6 ×

in solution in carbon tetrachloride proceeds via the reaction 2N₂O₅ (soln) → 4NO₂ (soln) + O₂ (soln)
The reaction is first order and has a rate constant of 4.82 × The decomposition of in solution in carbon tetrachloride proceeds via the reaction 2N2O5 (soln) → 4NO2 (soln) + O2 (soln) The reaction is first order and has a rate constant of 4.82 × at 64 °C.If the reaction is initiated with 0.072 mol in a 1.00-L vessel,how many moles remain after 151 s? A) 0.067 B) 0.074 C) 0.035 D) 9.6 E) 1.6 ×

at 64 °C.If the reaction is initiated with 0.072 mol in a 1.00-L vessel,how many moles remain after 151 s?

Quizplus · Accepted Answer

The Answer of The decomposition of in solution in carbon tetrachloride proceeds via the reaction 2N₂O₅ (soln)→ 4NO₂ (soln)+ O₂ (soln) The reaction is first order and has a rate constant of 4.82 × at 64 °C.If the reaction is initiated with 0.072 mol in a 1.00-L vessel,how many moles remain after 151 s?

The Decomposition of in Solution in Carbon Tetrachloride