Calculate the number of moles of excess reactant that will be left-over when 56.0 g of CaCl₂ react with 64.0 g of Na₂SO₄: CaCl₂ + Na₂SO₄ CaSO₄ + 2NaCl

Question

Quizplus · Accepted Answer

1. Calculate the number of moles of each reactant:

n(CaCl2) = 56.0 g / 111.0 g/mol = 0.504 moles
n(Na2SO4) = 64.0 g / 142.0 g/mol = 0.451 moles

2. Identify the limiting reactant:

According to the balanced equation, 1 mole of CaCl2 reacts with 1 mole of Na2SO4. Therefore, the limiting reactant is Na2SO4 because it has the smaller number of moles.

3. Calculate the number of moles of the product:

n(CaSO4) = n(Na2SO4) = 0.451 moles

4. Calculate the number of moles of excess reactant:

n(CaCl2) excess = n(CaCl2) - n(CaSO4) = 0.504 moles - 0.451 moles = 0.053 moles

Therefore, the answer is A) 0.0540 moles, which is the closest value to 0.053 moles.

Calculate the Number of Moles of Excess Reactant That Will