A Cessna aircraft has a lift-off speed of 135 km/h.What minimum constant acceleration does this require if the aircraft is to be airborne after a take-off run of 260 m? A)2.70 m/s² B)1.35 m/s² C)3.38 m/s² D)5.41 m/s² E)2.03 m/s²

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Quizplus · Accepted Answer

To find the minimum constant acceleration, use the formula $ v^2 = u^2 + 2as $, where $ v = 135 $ km/h (converted to 37.5 m/s), $ u = 0 $, and $ s = 260 $ m. Solving for $ a $ gives $ a = \frac{v^2}{2s} = \frac{(37.5)^2}{2 \times 260} = 2.70 $ m/s².

A Cessna Aircraft Has a Lift-Off Speed of 135 Km/h