A rock is thrown straight up with an initial velocity of 25.0 m/s.What maximum height will the rock reach before starting to fall downward? (Take acceleration due to gravity as 9.80 m/s². ) A)39.9 m B)15.9 m C)63.8 m D)31.9 m E)47.8 m

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Quizplus · Accepted Answer

The maximum height can be calculated using the formula $ h = \frac{v^2}{2g} $, where $ v = 25.0 \, \text{m/s} $ and $ g = 9.80 \, \text{m/s}^2 $. Plugging in the values, $ h = \frac{(25.0)^2}{2 \times 9.80} = 31.9 \, \text{m} $.

A Rock Is Thrown Straight Up with an Initial Velocity