A rock is thrown straight up with an initial velocity of 17.6 m/s.What time interval elapses between the rock's being thrown and its return to the original launch point? (Acceleration due to gravity is 9.80 m/s². ) A)3.60 s B)1.80 s C)2.70 s D)3.06 s E)3.96 s

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Quizplus · Accepted Answer

The time to reach the highest point is given by t = v/g = 17.6 m/s / 9.80 m/s² = 1.80 s. The total time for the round trip is twice this, so 2 * 1.80 s = 3.60 s.

A Rock Is Thrown Straight Up with an Initial Velocity