The angular frequency of rotation of electron on the second Bohr orbit is A)3.67 * 10¹⁵ rad/sec B)4.98 * 10¹⁵ rad/sec C)5.34 * 10¹⁵ rad/sec D)5.17 * 10¹⁵ rad/sec E)5.71 * 10¹⁵ rad/sec

Question

Quizplus · Accepted Answer

The angular frequency of rotation of an electron on the nth Bohr orbit is given by:ω = (2π/h) * (Ze²/4πε₀n²)where:h is Planck's constantZ is the atomic numbere is the charge of an electronε₀ is the permittivity of free spacen is the principal quantum numberFor the second Bohr orbit (n = 2), we have:ω = (2π/h) * (Ze²/4πε₀(2)²)= (2π/h) * (Ze²/16πε₀)Substituting the values of h, Z, e, and ε₀, we get:ω = (2π * (1.602 * 10^-19 C)² / (6.626 * 10^-34 J s) * (16 * 8.85 * 10^-12 F/m))= 4.98 * 10^15 rad/sTherefore, the correct answer is D) 4.98 * 10^15 rad/sec.

The Angular Frequency of Rotation of Electron on the Second