He⁺ is a helium atom with one electron missing.Treating this like a hydrogen atom,what is the first excited state of this atom? A)-6.40 eV B)-13.6 eV C)-54.4 eV D)-76.8 eV E)-152.2 eV

Question

Quizplus · Accepted Answer

Since the atom has only one electron, we can treat it like a hydrogen atom. Therefore, the energy of the first excited state of the atom is given by:
E = -13.6 eV / n^2, where n is the quantum number of the excited state.
For the first excited state, n=2, so:
E = -13.6 eV / 2^2 = -3.4 eV
However, since the atom is now a helium ion with a +1 charge, the total energy of the first excited state is:
E = -3.4 eV / 2 = -1.7 eV
Converting to electron volts gives:
E = -1.7 eV * (1.602 x 10^-19 J/eV) = -2.72 x 10^-19 J = -17.0 eV (rounded to one decimal place).
Therefore, the best choice for the energy of the first excited state is B) -13.6 eV.

He+ Is a Helium Atom with One Electron Missing

He⁺ Is a Helium Atom with One Electron Missing