Two isolated spheres have the same electric potential at their surface,but sphere A has twice the charge of sphere B.How is the radius of sphere A related to the radius of sphere B?

Question

Quizplus · Accepted Answer

The electric potential V at the surface of a sphere is given by V = kQ/R, where Q is the charge, R is the radius, and k is Coulomb's constant. Since both spheres have the same potential, kQ_A/R_A = kQ_B/R_B. Given Q_A = 2Q_B, we have 2Q_B/R_A = Q_B/R_B, leading to R_A = 2R_B.

Two Isolated Spheres Have the Same Electric Potential at Their