Two isolated spheres have the same electric potential at their surface,but sphere A has twice the radius of sphere B.How is the charge on sphere A related to the charge on sphere B?

Question

Quizplus · Accepted Answer

The electric potential $V$ at the surface of a sphere is given by $V = \frac{kQ}{r}$, where $k$ is Coulomb's constant, $Q$ is the charge, and $r$ is the radius of the sphere. Since both spheres have the same electric potential but sphere A has twice the radius of sphere B ($r_A = 2r_B$), for the potentials to be equal, sphere A must have twice the charge of sphere B to compensate for its larger radius. This makes the charge on sphere A twice that of sphere B ($2Q_B = Q_A$).

Two Isolated Spheres Have the Same Electric Potential at Their