Consider a cubical box that contains a charge distribution of total charge q = 6.40 C.The total electric flux through 5 of the 6 sides is = 3.90 *105 Nm2/C.What is the electric flux through the remaining sixth surface of the box (in Nm2/C) ? 
A) 3.33 * 105
B) 3.90 * 105
C) 4.56 * 105
D) 5.34 * 105
E) 6.24 * 105
Correct Answer:
Verified
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