A small charge is in a constant vertical electric field E = 1.32 * 10³ N/C in the positive y-direction.If the charge has a mass of 0.022 kg and its acceleration is -1.0 m/s²,what is the charge? There is no gravity.

Question

Quizplus · Accepted Answer

The force on the charge is given by F = qE, where q is the charge. The direction of the force will be opposite to the direction of the electric field since the charge is negative.

Using Newton's second law, we can relate the force to the acceleration: F = ma.

Therefore, qE = ma.

Solving for q, we get q = ma/E.

Plugging in the given values, we get q = (0.022 kg)(-1.0 m/s^2)/(1.32 N/C) = -0.017F1F1F11S1S1P0 C

Since the charge is negative, we take the absolute value to get the magnitude of the charge, which is 0.017 F1F1F1S1F1F1F10C.

The closest answer choice is B, which is -17 F1F1F1S1F1F1F10C, so the answer is B.

A Small Charge Is in a Constant Vertical Electric Field μ\muμ

A Small Charge Is in a Constant Vertical Electric Field $\mu$