A small charge of -11 $\mu$C is in a constant vertical electric field E = 2.32 * 10³ N/C in the positive y-direction.If the acceleration of the charge is -0.80 m/s²,what is the mass of the charge? There is no gravity.

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Quizplus · Accepted Answer

The force on the charge is F = qE = (-11 x 10^-6 C)(2.32 x 10^3 N/C) = -0.02552 N. Using F = ma, the mass m = F/a = -0.02552 N / -0.80 m/s² = 0.0319 kg, approximately 0.032 kg.

A Small Charge of -11 μ\muμ C Is in a Constant Vertical Electric Field E =

A Small Charge of -11 $\mu$ C Is in a Constant Vertical Electric Field E =