Consider the Following Reaction Which Has a ∆G˚' ≈ +30 $\Delta$

Consider the following reaction which has a ∆G˚' ≈ +30 kJ/mol.
malate + NAD⁺ → oxaloacetate + NADH + H⁺
In muscle cells, the reaction proceeds as written.Which of the following explains how the reaction occurs as written despite the positive value for $\Delta$ G^°'?

A) It is thermodynamically favored under standard conditions.
B) In the cell, it is kinetically favored, even though it's thermodynamically unfavorable.
C) The concentration of malate must be higher than oxaloacetate for this reaction to occur in the cell.
D) [H⁺] must be higher in muscle than under standard conditions, thus altering ∆G˚ to ∆G˚'.
E) None of the above