An ideal spring with a spring constant (force constant) of $22 \mathrm {~N} / \mathrm { m }$ is stretched from equilibrium to 2.9 m. How much work is done in the process?
A) 93 J
B) 186 J
C) 47 J
D) 121 J

Question

Quizplus · Accepted Answer

The work done by stretching the spring can be found using the formula: 
work = (1/2) * k * x^2 
where k is the spring constant and x is the displacement from equilibrium. 
Substituting the given values, we get: 
work = (1/2) * 22 * (2.9)^2 = 92.69 J (rounded to two decimal places) 
Therefore, the answer is A) 93 J, which is the closest option.

An Ideal Spring with a Spring Constant (Force Constant) Of 22