A proton that is initially at rest is accelerated through an electric potential difference of magnitude 500 V. How much kinetic energy does it gain?
(e = 1.60 × 10^-19 C)

Question

A proton that is initially at rest is accelerated through an electric potential difference of magnitude 500 V. How much kinetic energy does it gain? (e = 1.60 × 10^-19 C)

Quizplus · Accepted Answer

The kinetic energy gained by the proton is equal to the charge of the proton multiplied by the potential difference: KE = eV = (1.60 × 10^-19 C)(500 V) = 8.0 × 10^-17 J.

A Proton That Is Initially at Rest Is Accelerated Through