Determine the identity of the daughter nuclide from the alpha decay of ${ } _ { 86} ^ { 222 } $ Rn.

Question

Quizplus · Accepted Answer

In alpha decay, the daughter nuclide is formed by the emission of a helium nucleus, which has a mass number of 4 and an atomic number of 2. Therefore, the daughter nuclide will have a mass number that is 4 less than the parent nuclide, and an atomic number that is 2 less than the parent nuclide. In this case, the daughter nuclide would be $\begin{array} { c } 
218 \
84
\end{array}$ Po.

Determine the Identity of the Daughter Nuclide from the Alpha 86222{ } _ { 86} ^ { 222 } 86222​

Determine the Identity of the Daughter Nuclide from the Alpha ${ } _ { 86} ^ { 222 }$