Determine the identity of the daughter nuclide from the electron capture by $ { }_{4}^{7} \mathrm{Be} $

Question

Quizplus · Accepted Answer

Electron capture occurs when an inner orbital electron combines with a proton in the nucleus, forming a neutron and a neutrino. In this case, the electron capture by $ { }_{4}^{7} \mathrm{Be} $ can be represented as:
$$
{ }_{4}^{7} \mathrm{Be} + e^- \rightarrow { }_{3}^{7} \mathrm{Li} + \nu_e
$$
The daughter nuclide is therefore $ { }_{3}^{7} \mathrm{Li} $, which has 3 protons and 4 neutrons. The other answer choices are not consistent with this process.

Determine the Identity of the Daughter Nuclide from the Electron 47Be { }_{4}^{7} \mathrm{Be} 47​Be

Determine the Identity of the Daughter Nuclide from the Electron ${ }_{4}^{7} \mathrm{Be}$