Object 1 has three times the specific heat capacity and four times the mass of Object 2.The two objects are heated from the same initial temperature,T₀,to the same final temperature T_f.If during this process,if Object 1 absorbs energy through heating Q,the amount of energy absorbed through heating by Object 2 will be

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Quizplus · Accepted Answer

The amount of energy absorbed through heating by an object can be calculated using the formula $Q = mc\Delta T$, where $m$ is the mass, $c$ is the specific heat capacity, and $\Delta T$ is the change in temperature. Since Object 1 has three times the specific heat capacity and four times the mass of Object 2, and both are heated from the same initial to the same final temperature, the energy absorbed by Object 2 will be $\frac{1}{3}$ (due to the specific heat capacity) times $\frac{1}{4}$ (due to the mass) of the energy absorbed by Object 1, which equals $\frac{1}{12}$Q.

Object 1 Has Three Times the Specific Heat Capacity and Four