Consider the nuclear reaction: ⁷Li + ¹p → ⁴He + ⁴He.The known atomic masses are ⁷Li: 7.016005 u ${}^{4}_{2}$ He: 4.002603 u
¹p: 1.007825 u
What is the Q-value (or reaction energy) of this reaction? (1 u = 931.5 MeV/c²)

Question

Consider the nuclear reaction: ⁷Li + ¹p → ⁴He + ⁴He.The known atomic masses are ⁷Li: 7.016005 u

{}^{4}_{2}

He: 4.002603 u
¹p: 1.007825 u
What is the Q-value (or reaction energy) of this reaction? (1 u = 931.5 MeV/c²)

Quizplus · Accepted Answer

The Q-value is calculated by finding the mass defect and converting it to energy. The mass defect is the initial mass minus the final mass: (7.016005 u + 1.007825 u) - 2(4.002603 u) = 0.018624 u. Converting this to energy gives 0.018624 u * 931.5 MeV/u = 17.35 MeV.

Consider the Nuclear Reaction: 7Li + 1p → 4He 24{}^{4}_{2}24​ He: 4002603 U 1p: 1

Consider the Nuclear Reaction: ⁷Li + ¹p → ⁴He ${}^{4}_{2}$ He: 4002603 U
¹p: 1