When a neutron collides with a uranium-235 nucleus it can induce a variety of fission reactions.One such reaction is $^{235} _{92} U$ + ${}^{1}_{0}$ n → $^{140}_{54} Xe$ + ${}^{94}_{38}$ Sr + 2 ${}^{1}_{0}$ n The following mass values are known: $^{140}_{54} Xe$ : 139.921620 u ${}^{94}_{38}$ Sr: 93.915367 u $^{235} _{92} U$ : 235.043924 u ${}^{1}_{0}$ n: 1.008665 u
What mass of uranium is needed to produce a 10-kiloton yield? (1 u = 931.5 MeV/c² = 1.66054 × 10^-27 kg,1-kiloton yield = 5.0 × 10¹² J)

Question

When a neutron collides with a uranium-235 nucleus it can induce a variety of fission reactions.One such reaction is

^{235} _{92} U

+

{}^{1}_{0}

n →

^{140}_{54} Xe

+

{}^{94}_{38}

Sr + 2

{}^{1}_{0}

n The following mass values are known:

^{140}_{54} Xe

: 139.921620 u

{}^{94}_{38}

Sr: 93.915367 u

^{235} _{92} U

: 235.043924 u

{}^{1}_{0}

n: 1.008665 u
What mass of uranium is needed to produce a 10-kiloton yield? (1 u = 931.5 MeV/c² = 1.66054 × 10^-27 kg,1-kiloton yield = 5.0 × 10¹² J)

Quizplus · Accepted Answer

The Answer of When a neutron collides with a uranium-235 nucleus it can induce a variety of fission reactions.One such reaction is $^{235} _{92} U$ + ${}^{1}_{0}$ n → $^{140} _{54} Xe$ + ${}^{94}_{38}$ Sr + 2 ${}^{1}_{0}$ n The following mass values are known: $^{140} _{54} Xe$: 139.921620 u ${}^{94}_{38}$ Sr: 93.915367 u $^{235} _{92} U$: 235.043924 u ${}^{1}_{0}$ n: 1.008665 u What mass of uranium is needed to produce a 10-kiloton yield? (1 u = 931.5 MeV/c² = 1.66054 × 10^-27 kg,1-kiloton yield = 5.0 × 10¹² J)

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When a Neutron Collides with a Uranium-235 Nucleus It Can $^{235} _{92} U$