When a neutron collides with a uranium-235 nucleus it can induce a variety of fission reactions.One such reaction is $^{235} _{92} U$ + ${}^{1}_{0}$ n → $^{140}_{54} Xe$ + ${}^{94}_{38}$ Sr + 2 ${}^{1}_{0}$ n The following mass values are known:
$^{140}_{54} Xe$ : 139.921620 u

${}^{94}_{38}$ Sr: 93.915367 u

$^{235} _{92} U$ : 235.043924 u ${}\\^{1}_{0}n$ : 1.008665 u
How much energy is released in this reaction? (1 u = 931.5 MeV/c²)

Question

When a neutron collides with a uranium-235 nucleus it can induce a variety of fission reactions.One such reaction is

^{235} _{92} U

+

{}^{1}_{0}

n →

^{140}_{54} Xe

+

{}^{94}_{38}

Sr + 2

{}^{1}_{0}

n The following mass values are known:

^{140}_{54} Xe

: 139.921620 u

{}^{94}_{38}

Sr: 93.915367 u

^{235} _{92} U

: 235.043924 u

{}\\^{1}_{0}n

: 1.008665 u
How much energy is released in this reaction? (1 u = 931.5 MeV/c²)

Quizplus · Accepted Answer

The correct answer is A because the mass of the reactants is greater than the mass of the products, so the difference in mass is converted into energy according to Einstein's equation E=mc^2. The mass difference is (235.043924 u + 1.008665 u) - (139.921620 u + 93.915367 u + 2 * 1.008665 u) = 0.185937 u, which is equivalent to 185 MeV.

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