A bomb calorimeter has a heat capacity of 2.47 kJ/K.When a 0.105-g sample of a certain hydrocarbon was burned in this calorimeter,the temperature increased by 2.14 K.Calculate the energy of combustion for 1 g of the hydrocarbon.

Question

Quizplus · Accepted Answer

Firstly, we need to calculate the energy absorbed by the bomb calorimeter:

Q = CΔT
Q = (2.47 kJ/K) x 2.14 K
Q = 5.29 kJ

This is the energy released by the combustion of 0.105 g of the hydrocarbon. To calculate the energy of combustion for 1 g, we need to use the following conversion factor:

1 g / 0.105 g = 9.52

So, the energy of combustion for 1 g is:

E = (5.29 kJ) / 9.52
E = 0.555 kJ/g = 555 J/g

However, we need to change the sign of this value, since combustion is an exothermic process:

E = -555 J/g

Therefore, the best choice is B, which corresponds to -555 J/g.

A Bomb Calorimeter Has a Heat Capacity of 2