For the formation of 1 mol of nitrosyl chloride at a given temperature, $\Delta$ _rH = -36 kJ/mol.
NO(g) + ½ Cl₂(g) $\to$ NOCl(g)
The activation energy for this reaction is 67 kJ/mol.What is the activation energy for the reverse reaction?

Question

For the formation of 1 mol of nitrosyl chloride at a given temperature,

\Delta

_rH = -36 kJ/mol.
NO(g) + ½ Cl₂(g)

\to

NOCl(g)
The activation energy for this reaction is 67 kJ/mol.What is the activation energy for the reverse reaction?

Quizplus · Accepted Answer

The activation energy for the reverse reaction is the sum of the activation energy of the forward reaction and the enthalpy change of the reaction: 67 kJ/mol + 36 kJ/mol = 103 kJ/mol.

For the Formation of 1 Mol of Nitrosyl Chloride at a Given