Calculate the activation energy,E_a,for
N₂O₅(g) $\to$ 2 NO₂(g) + 1/2 O₂(g)
Given k (at 45.0 ^$\circ$C) = 5.79 $\times$ 10^-4 s^-1 and k (at 60.0 ^$\circ$C) = 3.83 $\times$ 10^-3 s^-1.(R = 8.314 J/K.mol)

Question

Calculate the activation energy,E_a,for
N₂O₅(g)

\to

2 NO₂(g) + 1/2 O₂(g)
Given k (at 45.0 ^$\circ$C) = 5.79

\times

10^-4 s^-1 and k (at 60.0 ^$\circ$C) = 3.83

\times

10^-3 s^-1.(R = 8.314 J/K.mol)

Quizplus · Accepted Answer

The activation energy can be calculated using the Arrhenius equation: ln(k2/k1) = (Ea/R) * (1/T1 - 1/T2). Plugging in the given values and solving for Ea gives approximately 111 kJ/mol.

Calculate the Activation Energy,Ea,for N2O5(g) →\to→ 2 NO2(g)+ 1/2 O2(g) Given K (At 45

Calculate the Activation Energy,E_a,for
N₂O₅(g) $\to$ 2 NO₂(g)+ 1/2 O₂(g)
Given K (At 45