In an experiment,0.42 mol H₂ and 0.42 mol I₂ are mixed in a 1.00-L container,and the reaction forms HI.If K_c = 49.for this reaction,what is the equilibrium concentration of HI?
I₂(g) + H₂(g) 2HI(g)

Question

In an experiment,0.42 mol H₂ and 0.42 mol I₂ are mixed in a 1.00-L container,and the reaction forms HI.If K_c = 49.for this reaction,what is the equilibrium concentration of HI?
I₂(g) + H₂(g) In an experiment,0.42 mol H2 and 0.42 mol I2 are mixed in a 1.00-L container,and the reaction forms HI.If Kc = 49.for this reaction,what is the equilibrium concentration of HI? I2(g) + H2(g) 2HI(g) A) 0.81 M B) 0.74 M C) 0.65 M D) 0.105 M E) 0.056 M

In an experiment,0.42 mol H<sub>2</sub> and 0.42 mol I<sub>2</sub> are mixed in a 1.00-L container,and the reaction forms HI.If K<sub>c</sub> = 49.for this reaction,what is the equilibrium concentration of HI? I<sub>2</sub>(g) + H<sub>2</sub>(g) 2HI(g) A) 0.81 M B) 0.74 M C) 0.65 M D) 0.105 M E) 0.056 M

2HI(g)

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The Answer of In an experiment,0.42 mol H₂ and 0.42 mol I₂ are mixed in a 1.00-L container,and the reaction forms HI.If K_c = 49.for this reaction,what is the equilibrium concentration of HI? I₂(g)+ H₂(g) 2HI(g)

In an Experiment,0