What is a correct cell notation for a voltaic cell based on the reaction below? Cu²⁺(aq)+ Pb(s)+ SO₄^2-(aq)$\to$ Cu(s)+ PbSO₄(s) A) Pb(s)| PbSO₄(s)|| Cu²⁺(aq)|| Cu(s) B) Cu(s)| Cu²⁺(aq)|| SO₄^2-(aq)| PbSO₄(s)| Pb(s) C) Cu(s)| Cu²⁺(aq),SO₄^2-(aq)| PbSO₄(s)| Pb(s) D) Cu(s)| Cu²⁺(aq),SO₄^2-(aq)|| PbSO₄(s)|| Pb(s) E) Pb(s)| PbSO₄(s)| SO₄^2-(aq)|| Cu²⁺(aq)|| Cu(s)

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Quizplus · Accepted Answer

In a voltaic cell, the anode (oxidation) is on the left and the cathode (reduction) is on the right. Pb(s) oxidizes to PbSO4(s) and Cu2+ reduces to Cu(s). The correct notation is Pb(s)| PbSO4(s)| SO42-(aq)|| Cu2+(aq)|| Cu(s).

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