Consider the following half-reactions:
Ag⁺(aq) + e^- $\to$ Ag(s) $~~~~~~~~$ $~~~~~~~~$ E^$\circ$ = +0.80 V
Cu²⁺(aq) + 2 e^- $\to$ Cu(s) $~~~~~~~~$ $~ ~~ ~$ E^$\circ$ = +0.34 V
Pb²⁺(aq) + 2 e^- $\to$ Pb(s) $~~~~~~~~$ $~~ ~ ~~$ E^$\circ$ = -0.13 V
Fe²⁺(aq) + 2 e^- $\to$ Fe(s) $~~~~~~~~$ $~~ ~ ~~$ E^$\circ$ = -0.44 V
Al³⁺(aq) + 3 e^- $\to$ Al(s) $~~~~~~~~$ $~~~ ~ ~$ E^$\circ$ = -1.66 V
Which of the above metals or metal ions will oxidize Pb(s) ?

Question

Consider the following half-reactions:
Ag⁺(aq) + e^-

\to

Ag(s)

~~~~~~~~

~~~~~~~~

E^$\circ$ = +0.80 V
Cu²⁺(aq) + 2 e^-

\to

Cu(s)

~~~~~~~~

~ ~~ ~

E^$\circ$ = +0.34 V
Pb²⁺(aq) + 2 e^-

\to

Pb(s)

~~~~~~~~

~~ ~ ~~

E^$\circ$ = -0.13 V
Fe²⁺(aq) + 2 e^-

\to

Fe(s)

~~~~~~~~

~~ ~ ~~

E^$\circ$ = -0.44 V
Al³⁺(aq) + 3 e^-

\to

Al(s)

~~~~~~~~

~~~ ~ ~

E^$\circ$ = -1.66 V
Which of the above metals or metal ions will oxidize Pb(s) ?

Quizplus · Accepted Answer

Ag⁺(aq) and Cu²⁺(aq) will oxidize Pb(s) because they have more positive reduction potentials than Pb²⁺(aq).

Consider the Following Half-Reactions: Ag+(aq)+ E- →\to→ Ag(s) ~~~~~~~~ ~~~~~~~~ E ∘\circ∘ = +0