What is the final temperature of 25.0 grams of water at 22.0°C after it absorbs
Of heat?

Question

What is the final temperature of 25.0 grams of water at 22.0°C after it absorbs 
Of heat?

Quizplus · Accepted Answer

We can use the formula q = m*c*ΔT, where q is the heat absorbed by the water, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature. Solving for ΔT, we get:

ΔT = q / (m*c)

Plugging in the given values, we get:

ΔT = 11000 J / (25.0 g * 4.18 J/(g°C))
ΔT = 104.9 °C

Therefore, the final temperature of the water is:

Tf = Ti + ΔT
Tf = 22.0°C + 104.9°C
Tf = 126.9°C

However, water can only exist as a liquid up to its boiling point, which is 100°C at standard pressure. Therefore, the final temperature of the water will be the boiling point of water (100°C).

What Is the Final Temperature of 25