Consider the reaction: 2 Al + 3Br₂ → 2 AlBr₃ Suppose a reaction vessel initially contains 5.0 mole Al and 6.0 mole Br₂.What is in the reaction vessel once the reaction has occurred to the fullest extent possible?

Question

Quizplus · Accepted Answer

Given the stoichiometry of the reaction (2 Al + 3 Br2 → 2 AlBr3), for every 2 moles of Al, 3 moles of Br2 are required. Starting with 5.0 moles of Al and 6.0 moles of Br2, the limiting reactant is Br2 because it will be completely consumed first. The reaction consumes 6.0 moles of Br2 (3 moles of Br2 for every 2 moles of Al), which corresponds to 4.0 moles of Al (since 2 moles of Al react with 3 moles of Br2). This leaves 1.0 mole of Al unreacted. The amount of AlBr3 produced is 4.0 moles, as 2 moles of Al produce 2 moles of AlBr3, and 4 moles of Al used will produce 4 moles of AlBr3. Therefore, the vessel will contain 1.0 mole of Al, 0 mole of Br2 (since it's the limiting reactant and fully consumed), and 4.0 moles of AlBr3.

Consider the Reaction: 2 Al + 3Br2 → 2 AlBr3

Consider the Reaction: 2 Al + 3Br₂ → 2 AlBr₃