What is the change in the boiling point of a solution made by dissolving 14.7 g of C₆H₁₂O₆ into
Of water? The density of water is
And
.

Question

What is the change in the boiling point of a solution made by dissolving 14.7 g of C₆H₁₂O₆ into Of water? The density of water is And .

Quizplus · Accepted Answer

First, we need to calculate the molality of the solution: molality = moles of solute / mass of solvent in kg mass of water = volume of water x density of water = 11ea8a6b_bbc7_d2a8_9ee3_71fd5757cf67_TB6109_11 x 11ea8a6b_bbc7_d2a9_9ee3_6fe07ec26c9a_TB6109_11 = 981 g molar mass of C₆H₁₂O₆ = (12x1) + (32x1) + (16x4) + 16 + 14 + (32x1) = 224 g/mol moles of C₆H₁₂O₆ = mass / molar mass = 14.7 / 224 = 0.0656 mol molality = 0.0656 / 0.981 = 0.067 mol/kg Next, we use the formula for the change in boiling point: ΔTb = Kb x molality where Kb is the molal boiling point elevation constant for water and is equal to 0.512°C/m. ΔTb = 0.512 x 0.067 = 0.034 C or 0.279°C (rounded to three significant figures) Therefore, the correct answer is D.

What Is the Change in the Boiling Point of a Solution