What is the change in the freezing point of a solution made by dissolving
Of C₆H₁₂O₆ into
Of water? The density of water is
And

Question

What is the change in the freezing point of a solution made by dissolving Of C₆H₁₂O₆ into Of water? The density of water is And

Quizplus · Accepted Answer

To calculate the change in freezing point, we use the formula: ΔTf = Kf x molality where Kf is the freezing point depression constant and molality is the number of moles of solute per kilogram of solvent. First, we need to calculate the molality of the solution: molality = moles of solute / mass of solvent in kg The mass of water is given as 500 g, which is 0.5 kg. mass of C₆H₁₂O₆ = 200 g = 0.2 kg moles of solute = mass of solute / molar mass of solute molar mass of C₆H₁₂O₆ = 338 g/mol moles of solute = 25 g / 338 g/mol = 0.074 moles molality = 0.074 moles / 0.5 kg = 0.148 mol/kg Now, we can calculate the change in freezing point: ΔTf = Kf x molality The freezing point depression constant for water is given as 1.86°C/m. ΔTf = 1.86°C/m x 0.148 mol/kg = 0.27528°C Rounding to two significant figures, the answer is 1.01°C.

What Is the Change in the Freezing Point of a Solution