A laser beam ($\lambda$ = 694 nm)is incident on two slits 0.100 mm apart.Approximately how far apart (in m)will the bright interference fringes be on the screen 5.00 m from the double slits? A)3.47 *10 ^- ³ B)3.47 * 10 ^- ² C)3.47 * 10 ^- ⁴ D)3.47 *10 ^- ⁶ E)3.47 * 10 ^- ⁵

Question

Quizplus · Accepted Answer

The distance between fringes for double slit interference is given by: 
Δy = λD/d 
where λ is the wavelength of light, D is the distance between the slits and the screen, and d is the distance between the slits. 
Substituting the given values, we get: 
Δy = (694 nm)(5.00 m)/(0.100 mm) 
Δy = 3.47 mm 
Converting to meters, we get: 
Δy = 3.47 × 10^-3 m 
Therefore, the best choice is B.

A Laser Beam λ\lambdaλ = 694 Nm)is Incident on Two Slits 0

A Laser Beam $\lambda$ = 694 Nm)is Incident on Two Slits 0