Two slits separated by 0.050 mm are illuminated with green light ($\lambda$= 540 nm).How many bands of bright lines are there between the central maximum and the 12-cm position? (The distance between the double slits and the screen is 1.0 m. )
A)1111
B)111
C)11
D)1
E)11111

Question

Quizplus · Accepted Answer

The distance between the double slits and the screen is given as 1.0 m. 
The formula for calculating the distance between the central maximum and the nth bright band is given by:

y = nλD/d

where, 
y = distance between the central maximum and the nth bright band 
λ = wavelength of light 
D = distance between the double slits and the screen 
d = distance between the two slits

Substituting the given values, we get:

y = n(540 x 10^-9 m)(1.0 m)/(0.050 x 10^-3 m)

y = 10.8 x 10^-3 n

To find the number of bright bands between the central maximum and the 12 cm position, we need to find the value of n such that y = 0.12 m (12 cm).

n = (0.12 m)/(10.8 x 10^-3 m n) = 11

Therefore, there are 11 bright bands between the central maximum and the 12-cm position. Hence, the answer is C) 11.

Two Slits Separated by 0 λ\lambdaλ = 540 Nm)How Many Bands of Bright Lines Are There Between the Light

Two Slits Separated by 0 $\lambda$ = 540 Nm)How Many Bands of Bright Lines Are There Between the Light