In a double slit experiment,the distance between the slits is 0.2 mm and the distance to the screen is 100 cm.What is the phase difference (in degrees)between the waves from the two slits arriving at a point 5 mm from the central maximum when the wavelength is 400 nm? (Convert your result so the angle is between 0 and 360 $\degree$. )
A)90 $\degree$
B)180 $\degree$
C)270 $\degree$
D)360 $\degree$
E)160 $\degree$

Question

Quizplus · Accepted Answer

The path difference is given by $ \Delta x = \frac{d \cdot x}{L} $, where $ d = 0.2 $ mm, $ x = 5 $ mm, and $ L = 100 $ cm. The phase difference $ \Delta \phi $ is $ \frac{2\pi}{\lambda} \Delta x $. Converting to degrees, the phase difference is 180°.

In a Double Slit Experiment,the Distance Between the Slits Is °\degree°

In a Double Slit Experiment,the Distance Between the Slits Is $\degree$